Create dictionary s3 based on s1 excluding keys that appear in dictionary s2

In Python, dictionaries are widely used data structures that store key-value pairs. Sometimes, we need to create a new dictionary by excluding keys that appear in another dictionary. This can be achieved by iterating over the keys of the original dictionary and checking if they exist in the second dictionary.

To create a new dictionary s3 based on s1 and excluding keys that appear in s2, we can use a simple loop. We iterate over the keys of s1 and check if each key exists in s2. If it does not exist, we add the key-value pair to the new dictionary s3.

This process allows us to create a new dictionary that contains only the key-value pairs from s1, excluding any keys that appear in s2. It is a useful technique when we need to filter out certain keys from a dictionary and create a new dictionary based on the filtered results.

Step 1: Define the dictionaries

In this step, we will define the dictionaries that we will be working with. We have three dictionaries:

s1: This dictionary contains the original set of key-value pairs. It is the dictionary from which we will be excluding keys.

s2: This dictionary contains the keys that we want to exclude. It serves as a reference dictionary for the keys that should not appear in the final dictionary, s3.

s3: This is the dictionary that we will be creating. It will be based on the dictionary s1, but will exclude the keys that are present in s2.

Step 2: Identify keys in s1 that also exist in s2

To create the dictionary s3 based on s1 and exclude keys that appear in s2, we need to identify the keys in s1 that also exist in s2. This will allow us to exclude those keys when creating s3.

Step 3: Create dictionary s3 by excluding common keys

In order to create dictionary s3, we need to exclude the keys that are common between dictionary s1 and dictionary s2. This means that we only want to keep the keys in s1 that do not appear in s2.

To achieve this, we can iterate over the keys in s1, and check if each key exists in s2. If the key does not exist in s2, we add it to s3 along with its corresponding value.

KeyValue
key1value1
key3value3
key4value4

In the example above, the keys «key1», «key3», and «key4» are present in s1 but not in s2. Therefore, we include them in s3 along with their corresponding values. The resulting dictionary s3 consists only of these unique keys and their values.

By following this process, we can easily create dictionary s3 by excluding the common keys between s1 and s2.

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